Taken from an email from Trey:

"Chris, the scenario you present in Option 1 is the correct interpretation. After checking the original intent with the factory/board, it is agreed that in your case at 285lbs, you'll need 32.5lbs of additional weight onboard secured in the denoted location(s). If you or anyone else have any questions/concerns, please call me.

Trey Brown
N20 Class Director
N20 1017"

These were the options presented:

Option #1: Two crew weighting 285#, Required minimum of 325#, difference is 40#. Only the first 25# being required with only half of the remaining 15# being required resulting in a corrected crew weight total of 317.5#.

The math: 40#s - 25#s = 15#s * 0.5 =7.5#s + 25#s = 32.5#s

Corrector weight needed: 32.5#


Option #2: Since 40# is required then only half of the additional required weight is needed resulting in a corrected crew weight total of 305#.

The math: 40#s * 0.5 = 20#s

Corrector weight needed: 20#


Option #3: Since 40# is required then an additional half of the 40#s is needed resulting in a corrected crew weight total of 345#.

The math: 40#s + 40#s * 0.5 = 60#s

Corrector weight needed: 60#


Option #4: Since 40# is required then the first 40# is needed with an additional half of the 15#s being also required resulting in a corrected crew weight total of 332.5#.

The math: 40 + (15 * 0.5) = 47.5#

Corrector weight needed: 47.5#