It would show the maximum loads that the rigging at that point had been subjected to. It had a graduated gauge and the reading would stay at the maximum that it had been subjected to. It was very interesting initially but as the max’ readings never ever approached the safe loadings given by the wire manufacturers, ...
Do you remember the purchase on the mainsheet system the boom length, hull length and wire thickness that was used on that boat ?
With such data a surprising simple but accurate way of estimating the rig loads exists. It goes something like this, for all you home builders and home modifiers out there.
Pitching moment mast =
(pull in mainsheet line * purchase mainsheet * length boom - righting moment crew+craft * 0.40
+ righting moment crew+craft/0.5*width boat * distance the sidestays are back from the mainbeam
This coveres respectively = moment due to mainsheet - moment due to sail drive + moment due to sidestay (only in centreline plane)
then
Forestay loading = Pitching moment mast / distance bridle points hull to mast step
Side stay loading = Righting moment crew+craft/0.5*width boat
Mast step load = mainsheet pull * purchase + forestay loading + side stay loading + weight rig
Bridle loads = forestay loading ; when the bridle wires are under a 30 degree angle (typical cat rig)
else
Bridle loads = 0.5 * forestay loading * length bridle wires / bridle strop height
Note that the highest stay loadings are achieved not with the crew trapping but with the crew hiking. For a trapezing crew an additional factor (deduction) needs to be added and that lowers the load in the sidestay significant which in turn lowers the forestay load.
Righting moment of a crew hiking can be estimated by :
Weight craft * 0.5 * width craft + crew weight * (width craft + 0.5 mtr)
Example : For a Taipan F16 with a 150 kg hiking crew (no trapezing) and 7:1 mainsheet purchase :
Righting moment hiking crew = 107 * 0.5 * 2.5 + 150 * (2.5 + 0.5) = 584 kgm
Pitching moment mast = 50 kg * 7 * 2.15 - 584 * 0.40 + 584/1.25 * 0.70 = 846 kgm
Forestay loading = 846 / 1.37 = 618 kg
Sidestay loading (hiking crew) = 584/1.25 = 467 kg
Mast step load = 50 * 7 + 618 + 467 + 25 = 1460 kg
Bridle loads = 0.5 * 618 * 1.22 / 0.7 = 539 kg (my Taiphoon has a larger bridle angle of 35 degrees)
This means that if all sailing conditions are perfectly stable (no dynamic forces c.q. gusts, shock loads, crew moving aroun) that the force situation needed to just keep the mast motionless on the vertical REQUIRES the above loadings. Without them the mast will fall down. Of course, dynamic forces will both increase and decrease the above loadings. A typical safety margin is to choose wires that can withstand 150% to 200% of the above calculated loadings.
The accuracy of the above numbers is around 5% from the modelling perspective. I've neglected the angles the stays make relative to the vertical and the pressure on the boom. These are however very small contribution. An example, A boom loading of 100 kg will only increase the mast step load by a mere 3.4 kg (=0.23%)!
I made a excel sheet with a more complex model then above and the results there don't differ by more then 5%. Making a similar model in some fancy designers software isn't going to produce more accurate results. Mostly because the same assumptions need to be made anyway and these are most limiting on the accuracy achieved.
Now all you homebuilders can design your own rigging.
Wouter